Examine whether the following equation is qua | vedclass

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Question

(A) Given equation: $\frac{x-2}{x+2} - \frac{x+2}{x-2} = \frac{3}{7}$.Taking $LCM$ on the left side: $\frac{(x-2)^2 - (x+2)^2}{(x+2)(x-2)} = \frac{3}{

Vedclass · Accepted Answer

Yes,it is a quadratic equation.

Vedclass · Answer

(A) Given equation: $\frac{x-2}{x+2} - \frac{x+2}{x-2} = \frac{3}{7}$.Taking $LCM$ on the left side: $\frac{(x-2)^2 - (x+2)^2}{(x+2)(x-2)} = \frac{3}{7}$.Expanding the terms: $\frac{(x^2 - 4x + 4) - (x^2 + 4x + 4)}{x^2 - 4} = \frac{3}{7}$.Simplifying the numerator: $\frac{-8x}{x^2 - 4} = \frac{3}{7}$.Cross-multiplying: $3(x^2 - 4) = -56x$.$3x^2 - 12 = -56x$.Rearranging into standard form $ax^2 + bx + c = 0$: $3x^2 + 56x - 12 = 0$.Since the equation is in the form $ax^2 + bx + c = 0$ where $a 
eq 0$,it is a quadratic equation.

Examine whether the following equation is quadratic or not: $\frac{x-2}{x+2} - \frac{x+2}{x-2} = \frac{3}{7}$

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